Question

What is the mass of 1.806x10^24 atoms of Mg?

Answer 1

Answer:

Let’s find the amount of CO in moles. 1 mole of a certain type of particle will always have roughly 6.02×10236.02×1023 particles, no matter what that particle is.

n CO = 1.806×10246.02×10231.806×10246.02×1023

n CO = 33

So, there are 3 moles of CO.

The atomic mass of C is 12 g/mole, while O is 16 g/mole. This means that the molecular mass of CO is 28 g/mole.

The mass of a particle is equal to the amount in moles times the atomic / molecular mass.

m CO = 3 × 28

m CO = 84

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