Question

What is the mass of 10 moles of sodium sulphite (Na₂S0₄)?

Answer 1

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Molecular weight of Na2SO3 = 2 X23 + 32+3X16 = 126g Number of moles of Na2SO3 =10 moles Mass of 10 moles of Na2SO3  =? Number of moles (n) = weight /molecular weight 10 = weight/ 126Weight = 10X 126= 1260g Mass of 10 moles of Na2SO3 = 1260g

Answer 2

Answer:

Mass of 10 moles of sodium sulphite is 1260 grams.

Explanation:

The given molecule is $Na_2SO_4$

The molar mass of Na = 23 g

Molar mass of S = 32 g

Mass of oxygen, O = 16

We can calculated the molecular mass of Sodium Sulphite. It can be calculated as :

$M=2\times 23+32+3\times 16=126\ g$

The number of moles is given by :

$n=\dfrac{Mass}{molecular \ mass}$

$Mass=n\times molecular \ mass$

$Mass=10\times 126$

Mass = 1260 grams

So, the mass of 10 moles of sodium sulphite is 1260 grams. Hence, this is the required solution.