What is the mass of 12.044× 1023 of he atom
Answers
Answered by
1
We know in one mole of He atom contains 6.022 × 10^23
So No. of moles present in He = 12.044 × 10^24 /6.022 × 10^24
= 2
So 2 moles of He are present
So mass of He is 8u
So No. of moles present in He = 12.044 × 10^24 /6.022 × 10^24
= 2
So 2 moles of He are present
So mass of He is 8u
Answered by
0
since 6.022*10 raised to power 23 atoms of carbon weighs 12gm........
so 12.044*10 raised to power 23 atoms of carbon weighs 24gm....
u may also calc. this as.....
1 mole carbon weighs 12gm... and
12.044*10 raised to power 23 contains 2 mole carbon atoms ...
so 24gm is the ans,
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