What is the mass of 2.5×10^23 atoms of nitrogen
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Answer:
Explanation:
number of ATOMS = moles × Na (avogadro's no.)
2.5×10²³ = 6.022 × 10²³ × moles
MOLES = 0.41 mol
moles= mass/molar mass
0.41= mass/14
mass = o.41 × 14
= 5.74 g
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