Question

What is the mass of 3.01×10^23 molecules of naoh

Answer 1

$\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}} \\ \\ \star \: \boxed{ \bold{ \green{given}}} \\ \\ \implies \: \sf{no. \: of \: molecules \: of \: naoh = 3.011 \times {10}^{23} } \\ \\ \star \: \boxed{ \bold{ \green{to \: find}}} \\ \\ \implies \: \sf \: mass \: of \: given \: no. \: of \: molecules \: of \: naoh \\ \\ \star \: \boxed{ \bold{ \green{formula}}} \\ \\ \implies \: \sf \: \boxed{ \pink{ \bold{mole = \frac{no. \: of \: molecules}{6.022 \times {10}^{23} }}}} \\ \\ \implies \: \sf \: \boxed{ \pink{ \bold{mass = mole \times molecular \: weight}}} \\ \\ \star \: \boxed{ \bold{ \green{calculation}}} \\ \\ \implies \: \sf \: mole = \frac{3.011 \times {10}^{23} }{6.022 \times {10}^{23} } = 0.5 \\ \\ \implies \: \sf \: mass = mole \times mw = 0.5 \times 40 = 20 g \\ \\ \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{\red{ \huge{ \sf{mass = 20 \: g}}}}}$