Question

What is the mass of 5.45 x 10-3 mol of glucose, C6 H12O6?

Answer 1

Answer:

moles=given mass ÷ molar mass

[mm of glucose:-12×6+1×12+16×6=180]

5.45×10^-3=mass÷180

mass=5.45×10^-3 × 180 = 981×10^-3 g or 0.981 g

Answer 2

The mass of $5.45 \times {10}^{ - 3}$ moles of glucose is 0.981 g.

Given:

$5.45 \times {10}^{ - 3}$ moles of glucose.

To Find:

The mass of $5.45 \times {10}^{ - 3}$ moles of glucose.

Solution:

To find the mass of glucose in given moles we will follow the following steps:

As we know,

The mass of hydrogen, carbon, and oxygen atoms is 1g, 12g, and 16g respectively.

The molecular mass of 1 mole of glucose(C₆H₁₂O₆) =

$12 \times 6 + 12 \times 1 + 16 \times 6 = 72 + 12 + 96 = 180g$

Now,

Mass of

$5.45 \times {10}^{ - 3}$ moles of glucose =

$5.45 \times {10}^{ - 3} \times 180 = 0.981g$

Henceforth, the mass of $5.45 \times {10}^{ - 3}$ moles of glucose is 0.981 g.

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