Question

What is the mass of 56 cm³ of carbon monoxide at STP?​

Answer 1

Answer:

0.07gm

Explanation:

At STP, 1 mole of any gas has a volume of 22.4 L.

Molar mass of CO = 12 + 16 = 28 g/mol

Therefore,

22.4 L ( 22400 cm3) is the volume of 28g CO at STP

56 cm3 will be the volume of (28/22400) x 56 = 0.07 g of CO at STP.

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