what is the mass of 56 cm3 of carbon monoxide at STP
Answers
Answered by
42
Molar mass of CO = 12 + 16 = 28 g/mol. Therefore, 22.4 L ( 22400 cm3) is the volume of 28g CO at STP. 56 cm3 will be the volume of (28/22400) x 56 = 0.07 g of CO at STP.
Answered by
3
Answer:
0.07
Explanation:
Same as given above ☺️
Similar questions