what is the mass of 6.02 x 10 to the power of 23 atoms of aluminum?
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Explanation:
One mole of aluminum atoms has a mass of 26.98 grams, and contains 6.02×1023 atoms. Dividing 26.986.02×1023 yields a mass of 4.48×10−23 g for one aluminum atom.
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Answer:
One mole of aluminum atoms has a mass of 26.98 grams, and contains 6.02×1023 atoms. Dividing 26.986.02×1023 yields a mass of 4.48×10−23 g for one aluminum atom
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