Physics, asked by Rkaran2629, 1 year ago

What is the mass of a body that weighs 1n at a place where g = 9.8m/s2?

Answers

Answered by choicebussiness
61

Weight(newton)= mass(Kg) x acceleration due to gravity (9.8m/s² in this case)

1= mass x 9.8

mass= 1÷9.8 = 0.102kg = 102 grams

hope it helps:)

Answered by ushmagaur
1

Answer:

The mass of a body that weighs 1 N at a place where g = 9.8 m/s^2 is 0.102 kg.

Explanation:

Given:-

The weight of a body is 1 N at a place where g = 9.8 m/s^2.

To find:-

The mass of a body.

As we know,

The weight of a body is equal to the mass of a body times the acceleration of the gravity, i.e.,

Weight of a body = Mass of a body × Acceleration of the gravity

Mathematically,

W = m × g

W = mg _____ (1)

It is given that the weight of a body = 1 N and g = 9.8 m/s^2.

Substitute the values of W and g in equation (1), we get

1 = m × 9.8

m = 1/9.8

m = 0.102 kg (Approx.)

Therefore, the mass of a body that weighs 1 N at a place where g = 9.8 m/s^2 is 0.102 kg.

#SPJ3

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