Question

what is the mass of a mettallic hollow cylinder pipe 24cm long with internal diameter 10cm and made up of metal 5mm thick density of the metal is 7g per cm3

Answer 1

$\Longrightarrow{\boxed{\bold{Answer: 2772\:g}}}$

$\textbf{\underline{Step-by-step explanation :- }}$

Internal diameter = 10 cm

Diameter = 2 × radius

10 cm = 2r

5 cm = radius

Now, 5 mm is thickness.

In cm, 5 mm = 5/10 cm = 0.5 cm

So outer radius = 5 cm + 0.5 cm = 5.5 cm

Volume of hollow pipe

= πh( R² - r² )

= 22/7 × 24 × ( 5.5² - 5² ) cm³

= 22/7 × 24 × ( 5.5 + 5 )( 5.5 - 5 )

= 22/7 × 24 × 10.5 × 0.5 cm³

$\bold{\huge{=\underline{396\:cm^3}}}$

As given, 1 cm³ weighs = 7 g

So, 396 cm³ weighs = 396 × 7 g

$\textbf{\huge{= \underline{2772 g}}}$

Answer 2

Answer:

hope it helps you