What is the mass of a photon of sodium light with a wavelength of 5890 Å?
[h= 6.626 × 10⁻³⁴ Js]
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Given conditions ⇒
Wavelength(λ) = 5890 Angstrom.
= 5890 × 10⁻¹⁰ m.
Plank's constant (h) = 6.626 × 10⁻³⁴ J-s.
Speed of the light(c)= 3 × 10⁸ m/s.
Using the Formula,
λ = h/mc
5890 × 10⁻¹⁰ = 6.626 × 10⁻³⁴/(m × 3 × 10⁸)
17670 × 10⁻² m = 6.626 × 10⁻³⁴
m = 0.00037 × 10⁻³²
m = 3.7 × 10⁻³⁶ kg.
Hence, the mass of the photons is 3.7 × 10⁻³⁶ kg.
Hope it helps.
Wavelength(λ) = 5890 Angstrom.
= 5890 × 10⁻¹⁰ m.
Plank's constant (h) = 6.626 × 10⁻³⁴ J-s.
Speed of the light(c)= 3 × 10⁸ m/s.
Using the Formula,
λ = h/mc
5890 × 10⁻¹⁰ = 6.626 × 10⁻³⁴/(m × 3 × 10⁸)
17670 × 10⁻² m = 6.626 × 10⁻³⁴
m = 0.00037 × 10⁻³²
m = 3.7 × 10⁻³⁶ kg.
Hence, the mass of the photons is 3.7 × 10⁻³⁶ kg.
Hope it helps.
Answered by
2
Answer:
Given conditions ⇒
Wavelength(λ) = 5890 Angstrom.
= 5890 × 10⁻¹⁰ m.
Plank's constant (h) = 6.626 × 10⁻³⁴ J-s.
Speed of the light(c)= 3 × 10⁸ m/s.
Using the Formula,
λ = h/mc
5890 × 10⁻¹⁰ = 6.626 × 10⁻³⁴/(m × 3 × 10⁸)
17670 × 10⁻² m = 6.626 × 10⁻³⁴
m = 0.00037 × 10⁻³²
m = 3.7 × 10⁻³⁶ kg.
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