what is the mass of a photon of sodium light with a wavelength of 5890 A°
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Hello Dear :-)
We know the formula
λ = h/mc
Where h is the plank constant = 6.62 × 10⁻³⁴ . J-s
c = 3 × 10⁸ m/s
λ =5890 × 10⁻¹⁰ m.
Now put this value in the formula .
λ = h/mc
5890 × 10⁻¹⁰ = 6.62 ×10⁻³⁴ /(m × 3 ×10⁸)
m = 6.62 × 10⁻³⁴ /(5890 × 10⁻¹⁰) (3 × 10⁸)
m= 6.62 ×10⁻³⁴/17670 × 10⁻² .
m= 3.74 × 10⁻³⁶
Hope it Helps. :-)
We know the formula
λ = h/mc
Where h is the plank constant = 6.62 × 10⁻³⁴ . J-s
c = 3 × 10⁸ m/s
λ =5890 × 10⁻¹⁰ m.
Now put this value in the formula .
λ = h/mc
5890 × 10⁻¹⁰ = 6.62 ×10⁻³⁴ /(m × 3 ×10⁸)
m = 6.62 × 10⁻³⁴ /(5890 × 10⁻¹⁰) (3 × 10⁸)
m= 6.62 ×10⁻³⁴/17670 × 10⁻² .
m= 3.74 × 10⁻³⁶
Hope it Helps. :-)
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