what is the mass of a photon of sodium light with a wavelength of 5890 armstrong
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"Wavelength=h/mv
so m=h/(wavelength*velocity)
=6.6*10^34/{[5894*10^(-10)]*3*10^8}
on solving we get
m=0.000373*10^(-32)
l = h / mc. l stands for wavelength
So m = h / c l
Hence m = 6.626*10^-34 / 3*10^8 * 589*10^-9
So m = 3.75*10^-36 kg
Compare this with atomic mass unit which is of the order of 10^-27
Hence mass of photon is not considerable
"
so m=h/(wavelength*velocity)
=6.6*10^34/{[5894*10^(-10)]*3*10^8}
on solving we get
m=0.000373*10^(-32)
l = h / mc. l stands for wavelength
So m = h / c l
Hence m = 6.626*10^-34 / 3*10^8 * 589*10^-9
So m = 3.75*10^-36 kg
Compare this with atomic mass unit which is of the order of 10^-27
Hence mass of photon is not considerable
"
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