Question

What is the mass of a sample of ca(oh)2 containing 18.069×1023OH Ions

Answer 1

Answer:

As each Ca(OH)2 molecule releases 2 OH- ions, No. of CA(OH)2 molecules =

(18.069 x 10²³)/2

= 9.0345 x 10²³ molecules.

No. of moles = No. of molecules/Avogadro's number

=(9.0345 x 10²³)/(6.023 x 10²³)

= 1.5 moles.

Mass of Ca(OH)2 = 1.5 x mass of each molecule.

= 1.5 x [1(40) + 2(16) + 2(1)]

= 1.5 x (74)

= 111 grams.