Question

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization of water is 2.25 x 10^6 J kg-1.

Answer 1

Hey Dear,

◆ Answer -

Mass of water sample = 2.38 g

● Explaination -

# Given -

Q = 2000 kJ = 2×10^6 J

c = 2.25×10^6 J/kg

T = 373 K

# Solution -

As we know amount of heat supplied is given by -

Q = m × c × T

2×10^6 = m × 2.25×10^6 × 373

m = 2×10^6 / 8.4×10^8

m = 0.00238 kg

m = 2.38 g

Therefore, 2.38 g of water is boiled.

Best luck...