Math, asked by habibullahraza8, 6 days ago

what is the mass of a solid iron Wrecking Ball of radius is 16 cm if the density of iron is 7.8 gm/cm3​

Answers

Answered by bhavnasunaniya
1

Step-by-step explanation:

59/60 because our lowest common denomination is 60 considering the factors of 3,4 and 5 ,if we adjust the rest accordingly we have 45/60+20/60+24/60 which gives us 89/60, we need to arrive at 30/60 which is the adjusted expression for 1/2 therefore we must subtract 59/60 from 89/60 which leaves 30/60 ,which then simplifies to 1/2

59/60 because our lowest common denomination is 60 considering the factors of 3,4 and 5 ,if we adjust the rest accordingly we have 45/60+20/60+24/60 which gives us 89/60, we need to arrive at 30/60 which is the adjusted expression for 1/2 therefore we must subtract 59/60 from 89/60 which leaves 30/60 ,which then simplifies to 1/2

59/60 because our lowest common denomination is 60 considering the factors of 3,4 and 5 ,if we adjust the rest accordingly we have 45/60+20/60+24/60 which gives us 89/60, we need to arrive at 30/60 which is the adjusted expression for 1/2 therefore we must subtract 59/60 from 89/60 which leaves 30/60 ,which then simplifies to 1/2

Answered by unknownbeing143
2

Answer:

we know m=v/p

volume of sphere is 4/3πr³ then

m=4/3π(16)²/7.8

341.34π/7.8

m=43.76π (approx)

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