What is the mass of aluminium which will be completely oxidized by 44.8 L of oxygen at STP. [Al= 27,0=16]
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Answer:
So we can say that 72 g of Oxygen will be oxidized by 44.8 l of Oxygen
Explanation:
1 mole = 22.4l
2 mole = 22.4 x 2 = 44.8l
so we can say that 2 moles of oxygen are to be used
4 Al + 3 O2 ----> 2 Al2O3
3 moles of O2 oxidizes 4 moles of Aluminium
2 moles of O2 oxidizes ? moles of Aluminium
(2 x 4)/3 = 8/3 = 2.66 moles
1 mole of Aluminium = 27g
2.66 moles of aluminium = ?
Weight of Aluminium = 2.667 x 27 = 72g
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