Chemistry, asked by mahijadhav06, 5 months ago

what is the mass of CaCo3 in its 500mL of 0.1m solution​

Answers

Answered by Anonymous
1

Let's see the chemical reaction between Calcium hydroxide and carbon dioxide....

Ca(OH)_2+CO_2\

CaCO_3+H_2OCa(OH)2+CO2→CaCO3+H2O

given, volume of Ca(OH)2 = 500mL = 0.5litre

concentration of Ca(OH)2 = 0.5M

so, number of mole of Ca(OH)2 = volume in Litre × concentration

= 0.5 Litre × 0.5M

= 0.25 mole

from reaction,

1 mole of Ca(OH)2 produces 1 mole of CaCO3.

so, 0.25 mole of Ca(OH)2 produces 0.25 mole of CaCO3.

hence, mole of CaCO3 = 0.25 mol

mass of CaCO3 = mole of CaCO3 × molar mass of CaCO3

= 0.25mol × 100g/mol

= 25g

hence, mass of CaCO3 = 25g

Similar questions