what is the mass of CaCo3 in its 500mL of 0.1m solution
Answers
Answered by
1
Let's see the chemical reaction between Calcium hydroxide and carbon dioxide....
Ca(OH)_2+CO_2\
CaCO_3+H_2OCa(OH)2+CO2→CaCO3+H2O
given, volume of Ca(OH)2 = 500mL = 0.5litre
concentration of Ca(OH)2 = 0.5M
so, number of mole of Ca(OH)2 = volume in Litre × concentration
= 0.5 Litre × 0.5M
= 0.25 mole
from reaction,
1 mole of Ca(OH)2 produces 1 mole of CaCO3.
so, 0.25 mole of Ca(OH)2 produces 0.25 mole of CaCO3.
hence, mole of CaCO3 = 0.25 mol
mass of CaCO3 = mole of CaCO3 × molar mass of CaCO3
= 0.25mol × 100g/mol
= 25g
hence, mass of CaCO3 = 25g
Similar questions
Math,
2 months ago
Hindi,
2 months ago
Math,
5 months ago
Social Sciences,
11 months ago
Social Sciences,
11 months ago
Science,
11 months ago