Question

What is the mass of calcium oxide is obtaind from decomposition of 50g of calcium carbonate?

Answer 1

Answer: Here is ur answer..

Answer 2

Explanation:

Given -

50g of CaCO3 decomposes.

To Find -

Mass of CaO

Now,

$CaCO_3 -> CaO + CO_2$

Molecular Mass of CaCO3 -

40 + 12 + 16 × 3

= 40 + 12 + 48

= 100 amu

$\bold{Mole(n) = \frac{Mass}{Gram \: molecular \: mass}} \\ \\ \frac{50}{100} \\ \bold{n_{CaCO_3} = \frac{1}{2} } \\ \\ \bold{From \: Stochiometery} \\ \frac{ n_{CaCO_3} }{ n_{CaO} } = \frac{1}{1} \\ It \: means, \: \\ n_{CaCO_3} = n_{CaO} \\\bold{n_{CaO} = \frac{1}{2} } \\ \\ We \: need \: to \: find \: \bold{Mass} \: of \: \bold{CaO} \\ \bold{Mass = n \times Gram \: molecular \: mass} \\ = \frac{1}{ \cancel2} \times \cancel{56} \\ = 28g \\ \\ Hence, \\ \bold{The \: mass \: of \: CaO \: = 28g}$