Question

what is the mass of carbon present in 0.5 mole of K4{Fe(CN)6}...???​

Answer 1

Answer:

I think it is K4[Fe(CN)]6 (Potassium ferrocyanide)

Molar mass of Given compound is 368.35 g/mol.

molar mass means mass of 1 mole of substances.

1 mole Potassium ferrocyanide contains 12 x 6 grams of carbon.

0.5 moles contains 12 x 3 = 36 grams of carbon.

Answer 2

mass of carbon present in 0.5 moles of K₄{Fe(CN)₆} is 36 grams

GIVEN

Number of moles of K₄{Fe(CN)₆} = 0.5

TO FIND

Mass of carbon present in the given mole of K₄{Fe(CN)₆}

SOLUTION

We can simply solve the above problem as follows -

We know.

$number \: of \: moles \: = \frac{molar \: mass \: }{given \: mass}$

Let us calculate the molar mass of potassium ferrocyanide = 4(166)+59 + 6(12) + 6(16)

= 368.3 g/mol

So,

1 mole of K₄{Fe(CN)₆} = 368.3 gram/mol

0.5 mole of K₄{Fe(CN)₆} = 368.3 × 0.5 = 184 grams

So, in 368.3 grams of potassium ferrocyanide mass of carbon is = 72 grams

In 184 grams of potassium ferrocyanide, the mass of carbon atom =

$\frac{72}{368.3} \times 184$

= 36 grams

Hence, the mass of carbon present in 0.5 moles of K₄{Fe(CN)₆} is 36 grams

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