What is the mass of fructose, also known as fruit sugar (C6H12O6), in a 1.40 x 10^2 mL sample of glucose solution that has a concentration of 1.23 M?
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I'm not certain why you'd think there would be any. You said it was a glucose solution, so all those numbers are irrelevant to the mass of fructose.Even if we assume that was just a typo, "1.40 x 102 mL" is confusing.
I'll calculate what I can, and maybe you can use that as an example to figure out whatever it is you were really trying to ask.
A 102 mL sample of a 1.23 M solution (of whatever) contains 0.0829 moles of solute. For either glucose or fructose (the molecular formulas are the same, it's the way the atoms are arranged that's different) 1 mole is 180 grams. 0.0829 moles x 180 grams per mole = 14.9 grams.
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