Question

What is the mass of glucose required to produce 44g of CO2 on completed combustion? Plz explain..

Answer 1

The empirical formula of glucose is C6H1206

To find the answer to this question, you will need to write a balanced equation of the reaction:

C6H12O6 + 6O2 ------> 6CO2 + 6H2O

What this means, is that 1 mole of the glucose burns to give 6 moles of CO2...the ratio of glucose:CO2 is 1:6

Calculate the moles of CO2;

mole= mass / molar mass  (molar mass CO2- 12+16x2=44)

       =44/ 44
       = 1 mole
our ratio was 1 mole of glucose to 6 moles of CO2
that means the moles of glucose required for this reaction is 1/6 moles

Therefore calculate the mass of Glucose;

mass of a compound= moles x its molar mass

molar mass of glucose, C6H12O6 =(12x6)+(1x12)+(16x6)
                                                   =72+12+96  = 190
hence mass = 190 x 1/6  = 31.667g

Therefore mass of glucose required is    31.667 grams

Answer 2

The correct ans is 30 I have a solved book and know correct ans but not explanation