What is the mass of hydrochloric acid required to neutralize 500 ml of 0.5 molar sodium hydroxide?
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Answered by
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First, calculate the number of moles of NaOH present in 5 grams. The molar mass of NaOH is 40 g/mol.
Number of moles of NaOH in 5 gram =
40
5
=0.125 moles.
The moles of HCl needed = moles of NaOH
M
1
V
1
=M
2
V
2
0.25×V
1
=0.125×1000
V
1
=
0.25
0.125×1000
=
Number of moles of NaOH in 5 gram =
40
5
=0.125 moles.
The moles of HCl needed = moles of NaOH
M
1
V
1
=M
2
V
2
0.25×V
1
=0.125×1000
V
1
=
0.25
0.125×1000
=
Answered by
0
ans
about 2.1 litres is the correct ans
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