Question

what is the mass of iron sulphide (Fe=56 and S=32)?​

Answer 1

Answer:

88 is your answer duet

Explanation:

hope it will help you

Answer 2

ANSWER

ANSWERMolecular weight of FeS

ANSWERMolecular weight of FeS 2

ANSWERMolecular weight of FeS 2

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2 will contain

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2 will contain 120

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2 will contain 12030

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2 will contain 12030

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2 will contain 12030 ×64=16 g of S.

ANSWERMolecular weight of FeS 2 =56+2(32)=120 g/mol.One mole (120 g) of FeS 2 will contain 2×32=64 g of S30 g of FeS 2 will contain 12030 ×64=16 g of S.Hence, the mass of sulfur contained in 30 grams of pyrites is 16 g.