Question

What is the mass of precipitate formed when 15mL of 16.9% solution of AgNO3 is mixed with 50mL of 5.8% NaCl solution? a.7g b. 14g c. 28g d. 3.5g

Answer 1

Answer:

7g

Explanation:

AgNO3+NaCl→AgCl+NaNO3

ForAgNO3,

V=50ml

V/W%=16.9%

W/50=16.9/100

WAgNO3=8.45g

nAgNO3=WAgNO3/MAgNO3

=0.05

ForNaCl,

V=50ml

W/V%=5.8%WNaCl=2.9g

nNaCl=WNaCl/MNaCl

=0.05

According to reaction AgCl(ppt) = 0.05 moles ×

Molar mass of AgCl = 0.05 × 142.8 = 7.14g ≈ 7g