Question

what is the mass of precipitate formed when 50 ml of 16.9 % solution of AgNo3 is mixed with 50 mL of 5.8 % NaCl solution​

Answer 1

Answer:

Let us calculate the moles of every compund.

Moles of AgNO3=  50∗16.9/100∗169.8  

=0.05mole  

Moles of NaCl = 50∗5.8/100∗58.5  

=0.05mole  

AgNo3 + NaCl ----> AgCl + NaNo3

Mass of AgCl = mole × molar mass

=0.05∗143.5  

=7.16g  

P.S.-Molar Mass of AgNO3 = 169.8 & NaCl = 58.5

Hope it Helps.

Explanation:

hope it helps please mark me brainliest