what is the mass of sulphur present in 1.2g molecules of SO2?
Answer:38.4g (Provide explanation!)
Answers
Answer:
sulphur in SO2
Mass of sulphur (32) in SO2 (1g molecules)
mass of sulphur (?) in SO2 (1.2g molecules)
32=1
?=1.2
(32×1.2)÷1
=38.4 g
38.4 g of Sulphur is present in 1.2 gram molecules of SO₂. Hence the correct option is option (3) 38.4 g.
Given:
The mass of SO₂ present = 1.2 g
To Find:
The mass of Sulphur present.
Solution:
The molar mass of SO₂ is equal to 68 grams.
→ The gram molecule of a substance is defined as the number of grams of the substance which is equivalent to the relative molecular mass of the given substance.
→ In other words, we can say that the gram molecules of a substance is equivalent to the number of moles of that substance.
∴ 1.2 gram molecule of SO₂ would be equivalent to 1.2 moles of SO₂.
∵ 32 grams of Sulphur are present in 1 mole of SO₂.
∴ The mass of Sulphur present in 1.2 moles of SO₂ = 1.2 × 32 = 38.4 g
Therefore 38.4 g of Sulphur is present in 1.2 gram molecules of SO₂. Hence the option (3) 38.4 is the correct option.
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