Question

what is the mass of sulphur present in 1.2g molecules of SO2?Answer:38.4g (Provide explanation!)​

Answer 1

Step-by-step explanation:

SO2 →molar mass→32+16*2→64g

1mol so2→1 mol s

64g→32g

1g→32/64→1/2

1.2g →1.2/2*64→38.4g

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Answer 2

Answer:

Sulphur in SO2

Mass of Sulphur (32) in SO2 (1g molecules)

mass of Sulphur (?) in SO2 (1.2g molecules)

32=1

?=1.2

(32×1.2)÷1

=38.4 g

Finding the mass from the given molecules:

By dividing the mass by the molar mass, determine how many moles you have. In the case of 1000 grammes, 1,000 g / 151.001 g/mol equals X g moles. The result is 6.022140857 x 1023 molecules per g mole, according to Avogadro's number. The number of MnSO4 molecules is the outcome.

Additional Information:

Using the mass listed in the Periodic Table, determine the atomic mass of each element. The molecular mass is calculated by adding the masses of all the elements in the molecule and multiplying the subscript (number of atoms) by the atomic mass of that element.

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