Question

what is the mass of the iron sphere of density of 8000 kgm-

3 and a volume of 2x10-3 m3.​

Answer 1

Answer:

Answers to all these questions, and many others, are based on the fact that pressure increases with depth in a fluid. This means that the upward force on the bottom of an object in a fluid is greater than the downward force on the top of the object. There is a net upward, or buoyant force on any object in any fluid. (See Figure 2.) If the buoyant force is greater than the object’s weight, the object will rise to the surface and float. If the buoyant force is less than the object’s weight, the object will sink. If the buoyant force equals the object’s weight, the object will remain suspended at that depth. The buoyant force is always present whether the object floats, sinks, or is suspended in a fluid.

Answer 2

Answer:

16 kg

Explanation:

Density = kg(m^-3)

volume = m^+3

therefore kg x m^-3 x m^+3 = kg x m^0   (Anything to the power of 0 = 1)

so, it equals to kg x 1 = kg

Mass = kg

therefore kg = kg(m^-3) x m^+3                {Mass = Density x Volume}

= 8000 x 2 x (10^-3) kg

= 16000 x (10^-3) kg

= 16.000 kg