Question

What is the mass of the precipitate formed when
50 mL of 16.9% (w/v) solution of AgNO, is mixed
with 50 mL of 5.8% (w/v) NaCl solution?
(Ag = 107.8, N = 14, O = 16, Na = 23, CI = 35.5)​

Answer 1

Answer:

◆Moles of AgNo3= 50*16.9/100*169.8

                           = 0.05mol

◆Moles of NaCl = 50*5.8/100*58.5

                       =0.05mol

Considering the reaction,

AgNo3 + NaCl➡AgCl + NaNo3

mass of AgCl = mole*molar mass

                       =0.05 *143.5

                       = 7.16 g