What is the mass of the precipitate formed
when 50 mL of 16.9% solution of AgNO, is
mixed with 50 mL of 5.8% NaCl solution?
(Ag = 107.8, N = 14, O = 16, Na = 23, CI =
35.5)
[2015]
Answers
Answered by
1
Answer:
AgNO
3
+NaCl→AgCl+NaNO
3
ForAgNO
3
,
V=50ml
V
W
%=16.9%
50
W
=
100
16.9
W
AgNO
3
=8.45g
n
AgNO
3
=
M
AgNO
3
W
AgNO
3
=0.05
ForNaCl,
V=50ml
V
W
%=5.8%
W
NaCl
=2.9g
n
NaCl
=
M
NaCl
W
NaCl
=0.05
AccordingtoreactionAgCl(ppt)=0.05moles×MolarmassofAgCl=0.05×142.8=7.14g≈7g
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