Question

What is the mass of the precipitate formed when 50ml of 16.9% solution of AgNO3 is mixed with 50ml of 5.8% Back solution

Answer 1

Moles of AgNO3 =  50 * 16.9/(100 * 170) =  0.05 (approx.)

Moles of NaCl =  5.8 * 5.8/(100 * 58.5) = 0.05

Reaction:-AgNO3    +    NaCl       ->            AgCl             +           NaNO30.05               0.05                                0                                 0 0                         0                             0.05 Hence, mass of the precipitate, AgCl = 0.05 * 143.5 => 7.16 g.