Question

What is the mass of urea (molar mass=60) that needs to be dissolved in 100 gm of water in order to decrease the vapour pressure of water by 25% at a definite temperature?​

Answer 1

Answer:

Given,

Force, F=5N

Acceleration,a=8  

Using, F=ma

5=m1 x 8

or m1=5/8 kg

For second mass,

Acceleration, a=24

Force, F=5 N

Again using F=ma

F=m2 x 24

or m2=5/24 kg

When both the masses are tied together,

Then total mass, m=m1+m2

m=(5/8)+(5/24)=20/24 kg

Now,

F=ma

or 5=(20/24)a

or a=6 $\\ \leq \left \{ {{y=2} \atop {x=2}} \right. x^{2} \geq \int\limits^a_b {x} \, dx jhijol\sqrt{x} \lim_{n \to \infty} a_n \sqrt[n]{x} \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \frac{x}{y} \alpha x_{123} \beta \sqrt[n]{x} \pi \neq \sqrt{x}$

Explanation:

$\lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x_{123} \sqrt[n]{x} \frac{x}{y}$

6afc9eaeab1ea381599faa44a6fad43c.pdf