Question

what is the mass of water formed when 8 gram of H2 reacts completely with O2 according to the reaction 2H2(g) + O2 (g) = 2H2O (l)​

Answer 1

Answer:

Mass of water formed = 72 g

Explanation:

Given:

2H₂(g) + O₂ (g) → 2H₂O (l)​

mass of H₂, w₁ = 8g

Let mass of H₂O formed be w₂

To find:

mass of H₂O formed, w₂ = ?

Step-by-step solution:

We know,

molar mass of H₂, M₁ = 2g mol⁻¹

molar mass of H₂O, M₂ = 18g mol⁻¹

no. of moles = $\frac{given mass(w)}{molar mass(M)}$

Now, from the equation, we know,

2 moles of H₂ gives 2 moles of H₂O

∴ $2 (\frac{w_{1} }{M_{1} } ) = 2 (\frac{w_{2} }{M_{2} } )$

⇒ $w_{2} = \frac{(8)(18)}{2}$

⇒ $w_{2} = 72 g$