Question

what is the mass percent of sodium hydroxide in a solution that is made by dissolving 8.00g NaOH in 50.00g H2O​

Answer 1

Given:

Mass of solute (NaoH) = 8.00g

Mass of solvent (H20) = 50.00g

To Find:

Mass percent of solute (NaoH) in the solution = ?

Step-wise Solution:

To find the mass percent of solute in the solution we need to apply the formula given below:

Percent by Mass (%m/m) = (Mass of solute (g) ÷ Mass of solution (g)) × 100

Mass of solution (g) = Mass of solute (g) + Mass of solvent (g)

Now, to determine mass percent of 8.00 g of NaoH dissolved in 50.00 g water steps are as follows:

Mass of solution (g) = 8.00 g (NaoH) + 50.00 g (Water)

                                 = 58.00 g of solution

Percent by Mass (% m/m)  = (8.00 g of solute ÷ 58.00 g of solution) × 100

                                             = (0.1379) × 100

                                             = 13.79 % m/m

Hence, the mass percent of NaoH in a solution is 13.79 % m/m.