Question

What is the mass percentage of carbon in
equimolar mixture of C2,H6
and C5H10

60
72
84
54​

Answer 1

7×12+16/7×12 whole multiplied by 100

100/84 into 100

10000/84

Answer 2

Answer:

The mass percentage of carbon in an equimolar mixture of C2H6 and C5H10 is 72.

Step-by-step explanation:

The total mass of the mixture is: Mass of C2H6 + Mass of C5H10

= (2x6 + 6x1) + (5x6 + 10x1)

= 18 + 40

= 58.

Mass of all carbon atoms in the mixture is = 7x6 = 42

Therefore mass percentage = $\frac{42}{58}$ × 100

≈ 72.

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