Question

what is the maximum acceleration of a platform that oscillates at amplitude of 2.20 and frequency 6.60Hz?​

Answer 1

Answer:

Explanation:

The acceleration amplitude is  am​=ω2xm​, where  ω  is the angular frequency (ω=2πf )  

Since there are  2π  radians in one cycle.  

Therefore, in this circumstance, we obtain  

am​=ω2xm​ =(2πf)2xm​=(2π(6.60Hz))2(0.0220m) =37.8m/s2

Answer 2

The acceleration amplitude is Am=ω²Xm

where ω is the angular frequency (ω=2πf )

Since there are 2π radians in one cycle.

Therefore, in this circumstance, we obtain

Am=ω²xm=(2πf)²Xm=(2π(6.60Hz))²(0.0220m)=37.8m/s²