Question

what is the maximum and minimum resistance that can be secured by combination of 3ohm 3ohm 6ohm​

Answer 1

Answer:

Three resistors of 3 ohm, 4 ohm, and 6 ohm are connected in parallel, the combination is connected in series with a cell of EMF 2 volt. What is the current through each resistors and the total current?

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R1=3ohm R2=4ohm,R3=6ohm

As the resistors are connected in parallel

1/Rtotal=1/3+1/4+1/6

1/Rtotal=(4+3+2)/12

1/Rtotal=9/12

Rtotal=12/9

Rtotal=4/3 ohm

Total current=Voltage /Rtotal

Itotal=2/(4/3)

Itotal=6/4

Itotal=3/2 Ampere

For resistance in the parallel ,voltage across each resistor is same and total current is sum of current through each resistor.

Current through R1=V/R1=2/3 Ampere

Current through R1=V/R2=2/4=1/2Ampere

Current through R1=V/R3=2/6=1/3Ampere