What is the maximum and minimum value of 3cosx +4sinx+5
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So the minimum value of 3cosx + 4sinx + 8 is -5+8 = 3. In general, and by the same reasoning, the maximum and minimum values of acosx+bsinx are ±√(a²+b²). The expression yields 3, and that is the lowest you can get.
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Answer:
The maximum and minimum values would be 13 and 3 respectively
Step-by-step explanation:
Just use the formula Y=asinx+or-bcosx ; then add or subtract the constant accordingly :)
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