Question

What is the maximum data rate of a channel with a bandwidth of 450 kHz if we use Eight levels of digital signaling.

Answer 1

We will calculate the maximum rate of data in the following way:

Explanation:

• Data rate implies the speed of data transfer via a channel.  

• Supposing an 8 Quadrature Amplitude Modulation (QAM), 3 bits/Hz of bandwidth can be transmitted per second.

• We have 450 KHz, so the maximum data rate achievable hypothetically will be -

• $450 KHz*3 bits/Hz/s=1350 Kbps\\= 1.35 Mbps$

• So, it is concluded that 1.35 Mbps is the maximum rate of data transfer of the given channel.