What is the maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water?
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The maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is greater than 0 but less than 50.
From IE:
eff = (TH– TC)/TH x 100%
= [(100 + 273) – (0 + 273)]/(100 + 273) x 100% Eff
= (100/373) x 100%
= 26.8 %
From IE:
eff = (TH– TC)/TH x 100%
= [(100 + 273) – (0 + 273)]/(100 + 273) x 100% Eff
= (100/373) x 100%
= 26.8 %
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