Question

What is the maximum height attained by a body thrown upwards with a velocity of

19.6 m/s? Take g= 9.8m/s2.​

Answer 1

Answer:

u=19.6,a=−9.8

using : s=ut+

2

at

2

when the body reaches ground displacement ,s=0

ut−

2

gt

2

=0

t(2u−gt)=0

we get t=0,

g

2u

since at t=0 body is projected so Time of flight=

g

2u

T=

9.8

2×19.6

T=4s

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