what is the maximum height of a ball thrown vertically upwards with a velocity of 49m/s
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0
Answer
49m/s answer
Explanation:
not sure
Answered by
1
Answer:
122.5m
Explanation:
Initial velocity= 49m/s (u)
Final velocity= 0 (v)
Acceleration due to gravity= -9.8m/s² (g)
By 3rd equation of motion
2gh=v²-u²
2×-9.8×h= 0² - 49²
19.6h=-49×49
h= -49×49/-19.6
h = 122.5 m
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