what is the maximum length of a pencil that can be kept in a rectangular box of dimensions 12cmx9cmx8cm is
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Diagonal - √ (8² + 6² + 2²) = 10.198 cm.
However the one end of the pencil is sharp and the other end is hexagonal. The width of the normal pencil is approx 6 mm
Therefore it would make a triangle at the end. The length of the vertical would be = 3.3 mm
Therefore maximum length of the pencil can be kept in the box would be - 9.866 cm
Its derived from below -
√ (8² + 6² + 2²) = √104 = √(4 x 26) = 2√26
However the one end of the pencil is sharp and the other end is hexagonal. The width of the normal pencil is approx 6 mm
Therefore it would make a triangle at the end. The length of the vertical would be = 3.3 mm
Therefore maximum length of the pencil can be kept in the box would be - 9.866 cm
Its derived from below -
√ (8² + 6² + 2²) = √104 = √(4 x 26) = 2√26
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