Question

What is the maximum length of a rod that can be kept inside a closed box of dimensions 10 m into 5 m into 3 m find the angle of orientation of the rod?

Answer 1

Hi Friend !!!

=======================

The maximum length of rod is its diagonal

$= \sqrt{10 \times 5 \times 3 } \\ \\ = \sqrt{50} \\ \\ = 5 \sqrt{2}$

= 5√2m

♡♥hope it helps u♥♡

Answer 2

Concept used:

Maximum Length of the rod = Diagonal of room

Formula used:

Diagonal of room = √(10+ b² + h²)

Calculation:

Diagonal of room = √(12+ b² + h²)

Diagonal of room = √(100 + 25+9)

Diagonal of room = √(100 + 25+9)

=> Diagonal of room = √134m

The maximum length of the rod is √139m

• $\alpha = \cos ^{ - 1} ( \frac{10}{ \sqrt{134} } )$
• $\beta = \cos {}^{ - 1} (\frac{5}{ \sqrt{134} } )$