Question

What is the maximum length of equal pieces of chocolates obtained by breaking two bars of chocolates 6 cm and 8 cm long?​

Answer 1

Step-by-step explanation:

From what i could make out, you seem to mean that when both ropes are cut into some equal parts , each of the final part should be of equal length. In that case, the solution is very simple.

Just find the hcf(highest common factor) of length of both rope, thats the answer!!!

Here lengths are 20 and 16. So its hcf will be 4.(Dont ask me how!!!) So the maximum length of each rope can be 4m only. Also the number of pieces will be 4 and 5 form longer and shorter one respectively. So total pieces are 9 with each one of them 4 m long.

Answer 2

Given,

Length of two chocolate bars = 6cm and 8cm

To find,

The maximum length of equal pieces that can be obtained by breaking the two bars.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Here, we have to find the HCF (Highest Common Factor) of the lengths of the two chocolate bars, in order to get the length of the maximum length of equal pieces.

So, HCF of the lengths is :

6 = 2×3

8 = 2×2×2

Common factor = 2

So, HCF = 2

Which means we can obtain a max. length of 2cm for the equal pieces that can be obtained from 2 bars.

(6÷2 = 3 equal pieces from first bar ; 8÷2 = 4 equal pieces from second bar)

Hence, maximum length of the equal pieces will be 2cm