Question

What is the maximum no.of emission lines when the excited electron of a H atom in n=6 drops to the ground state ?​

Answer 1

HELLO!

Your answer is 15! Check out the attachment for the solution.

Thanks!

Answer 2

$\mathfrak{ \huge{ \pink{ \underline{Answer}}}} \\ \\ \bigodot \: \blue{given} \\ \\ \implies \: excited \: state \: n2 = 6 \\ \implies \: ground \: state \: n1 = 1 \\ \\ \bigodot \: \blue{to \: find} \\ \\ \implies \: no. \: of \: spectral \: lines \: when \\ excited \: electron \: comes \: to \: ground \: state \\ \\ \bigodot \: \blue{formula} \\ \\ \implies \: \boxed{ \red{no. \: of \: spectral \: lines = \frac{n2(n2 - 1)}{2}}} \\ \\ \bigodot{ \blue{calculation}} \\ \\ \implies \: no. \: of \: spectral \: lines = \frac{6(6 - 1)}{2} = 15 \\ \\ \implies \: \boxed{ \boxed{ \green{no.of \: spectral \: lines = 15}}}$