What is the maximum no. of stereoisomers possible for compound CH3CH(OH)CH(OH)CH2CH3.
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Answer is 3
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The number of stereoisomers possible for H
3
C−CH(OH)−CH(OH)−CH
3
is :
Medium
Solution
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Correct option is C)
The number of stereoisomers possible for H
3
C−CH(OH)−CH(OH)−CH
3
is 3.
H
3
C−CH(OH)−CH(OH)−CH
3
has two chiral carbon atoms and is symmetrical, therefore n=2
Number of d and l isomers 2
n−1
=2
2−1
=2
Number of meso forms 2
n/2−1
=2
2/2−1
=2
2
=4
Total number of stereoisomers =2+4=6
Hence, the correct option is C
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