Question

What is the maximum number of emission lines when the excited electron of an h atom in n = 6 drops to the ground state?

Answer 1

Answer:

Max no. of lines = 15

Explanation:

The no. Of spectral lines = $\frac{n(n-1)}{2}$

Here, n = 6

Therefore, The no. Of spectral lines = $\frac{6(6-1)}{2}$

                                                            = 15